-(1/3)(x-1)^2=-12

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Solution for -(1/3)(x-1)^2=-12 equation: 


x in (-oo:+oo)

-((1/3)*(x-1)^2) = -12 // + 12

12-((1/3)*(x-1)^2) = 0

(-1/3)*(x-1)^2+12 = 0

12-1/3*(x-1)^2 = 0

12-1/3*(x-1)^2 = 0

2/3*x-1/3*x^2+35/3 = 0

2/3*x-1/3*x^2+35/3 = 0

1/3*(2*x-x^2+35) = 0

2*x-x^2+35 = 0

DELTA = 2^2-(-1*4*35)

DELTA = 144

DELTA > 0

x = (144^(1/2)-2)/(-1*2) or x = (-144^(1/2)-2)/(-1*2)

x = -5 or x = 7

1/3*(x+5)*(x-7) = 0

1/3*(x+5)*(x-7) = 0

( 1/3 )

1/3 = 0

x belongs to the empty set

( x+5 )

x+5 = 0 // - 5

x = -5

( x-7 )

x-7 = 0 // + 7

x = 7

x in { -5, 7 }

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